SOLVED:The Heaviside function of Example 1 has both absolute maximum and minimum values on the interval [-1,1] , but it is not continuous on that interval. Does this violate the Max-Min Theorem? Why?

Heaviside Step Function Video Lecture | Calculus - Mathematics

SOLVED: The graph of f(t) is given below:(Click on graph to enlarge)Represent f(t) using a combination of Heaviside step functions. Use h(t - a) for the Heaviside function shifted units horizontally:f(t) = (2t - 2)h(t - 1) - h(t - 4)] 6[h(t - 4) - h(t - 9)]Help (formulas)Find the Laplace transform F(s) of f(t) for s ≠ 0.F(s) = Lf(t)(((2/s^2) (1/s)) (e^-s)) - (((2/s^2) (7/s)) (e^(-4s))) ((6/s) (e^(-4s))) - ((6/ help (formulas)

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